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09.15.2008 at 04:18PM PDT, ID: 23733649
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6.6

Testing Windows user account for group membership

Asked by c0dejunkie in Lightweight Directory Access Protocol (LDAP), Visual Basic Programming, Active Directory

Tags: ,

I am attempting to add basic ActiveDirectory integration into a Visual Basic 6 (VB6) desktop application. I have found a number of methods to obtaining information from ActiveDirectory, however none have been able to successfully answer the simple question; "Is 'currentuser' a member of 'desiredgroup'?" Some of the solutions I have found so far have come close, allowing me to iterate through the ActiveDirectory objects, however this approach does not resolve multi-tier membership, e.g. User1 is a member of MyGroup which is a member of SuperGroup which is a member of DesiredGroup.

The closest I have come is with something akin to the following, using the ADO OLE DB connector and LDAP_MATCHING_RULE_IN_CHAIN, but I can't figure out the correct filter syntax to state I want any record for User1 where DesiredGroup is somewhere in the membership tree:

cmdRead.CommandText = "<LDAP://LocalHost>;(memberOf:1.2.840.113556.1.4.1941:=CN=User1);ADsPath, cn; base"

 --or maybe--

cmdRead.CommandText = "<WinNT://MyComputer>;(memberOf:1.2.840.113556.1.4.1941:=CN=DesiredGroup);ADsPath, cn; base"

Alternatively, the other solution path I have been working with is using the interfaces provided via ActiveDS.dll to connect with GetObject("WinNT://" & strComputer & "") and parse through the objects.

If anyone has some tips or helper routines that can help me get past this learning curve and achieve the function I am working toward with either of these solution trees, or some other that I have not come across yet, it would be much appreciated.Start Free Trial
 
 
[+][-]09.16.2008 at 05:24AM PDT, ID: 22487563

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About this solution

Zones: Lightweight Directory Access Protocol (LDAP), Visual Basic Programming, Active Directory
Tags: VB6, LDAP Filtering
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Solution Provided By: c0dejunkie
Participating Experts: 1
Solution Grade: A
 
 
 
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